Question

the sum of three consecutive multiples of 6 is 90 .find the numbr

Answer 1

Since they are consecutive multiples of 6, they should be in the form 6(n-1), 6(n), 6(n+1). Here we have sum is 90, 6(n-1)+6n+6(n+1)=18n=90. Therefore, n=5. Consecutive numbers are 24, 30, 36.

Answer 2

Here is your solution

Let,

The first multiple of 6 be x 

Second multiple = x+6 

Third multiple = x+6+6 = x+12 

A/q

x+x+6+x+12 = 90
=>3x + 18 = 90
=>3x = 90-18 = 72
=>x = 72/3 
=>x = 24

Hence,
x=24
x+6 = 30
x+12 = 36

So, the multiples are 24, 26 and 30.
 
Hope it helps you