Question

the sum of three consecutive multiples of 6is 126.find these three multiples. ​

Answer 1

Answer:

71,72,73

Step-by-step explanation:

let 3 consecutive multiples r x,x+1 ,x+2

x+x+1+x+2=216

3x +3 =216

3 (x+1)=216

x+1=216÷3

x+1=72

x=72-1

x=71

hence 3 multiples r 71 ,72 ,73