The sum of three consecutive multiples of 7 are 210. Find these multiples
Answers
Answered by
8
ANSWER:
THE THREE NUMBERS ARE 63, 70, 77
ASSUMPTION:
TAKE THE CONTINUOUS MULTIPLES AS 7x , 7(x + 1) , 7(x + 2)
GIVEN:
7x + 7(x + 1) + 7(x + 2) = 210
TO FIND:
7x , 7(x + 1) , 7(x + 2)
EXPLANATION:
7x + 7x + 7 + 7x + 14 = 210
21x + 21 = 210
DIVIDE BY 21 ON BOTH SIDES
x + 1 = 10
x = 9
7x = 7(9) = 63
7(x + 1) = 7(10) = 70
7(x + 2) = 7(11) = 77
THE THREE NUMBERS ARE 63, 70, 77
VERIFICATION:
63 + 70 + 77 = 21
HENCE THE THREE NUMBERS ARE 63, 70, 77
Answered by
5
Answer:
63,70,77
Step-by-step explanation:
Let the three consecutive multiples of 7 be 7x,7(x+1),7(x+2)
The sum of three consecutive multiples of 7 = 210.(given)
7x +7(x+1) +7(x+2) = 210
7x + 7x + 7 + 7x + 14 =210
21x + 21 =210
21x = 210 - 21
21x = 189
x = 189/21
x = 9
3 multiples are,7x9,7 x 10,7x11
63,70,77
Hope you understand..
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