Question

The sum of three consecutive multiples of 7 is /126​

Answer 1

The three multiples are 35, 42, 49

Let the sum of three consecutive multiples of 7 be,

(7x - 7) + 7x + (7x + 7) = 126

= 21x = 126

x = 6

So,

7x = 42

7x - 7 = 35

7x + 7 = 49

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