the sum of three consecutive multiples of 7 is 126
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Let first multiple of 7 be x
x,x+7,x+14
x+x+7+x+14=126
3x=126-21
3x=105
X=105/3
X=35
So consecutive numbers are 35,42,48
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x,x+7,x+14
x+x+7+x+14=126
3x=126-21
3x=105
X=105/3
X=35
So consecutive numbers are 35,42,48
Mark me brainlest and thank me
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