The sum of three consecutive multiples of 7 is 147 find the multiples
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Step-by-step explanation:
let the first number be x
They all are consecutive and multiple of 7
so , number are 7(x) + 7(x+1) + 7(x+2)
= 7(x) + 7(x+1) + 7(x+2)
= 21 x +21 = 147
= 21 x = 147 - 21
= 21 x = 126
= x = 126/21
= x = 6
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