The sum of three consecutive multiples of 7 is 315. Find the multiples.
Answers
Step-by-step explanation:
7 = 30
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Answer:- The multiples are = 98, 105, 112.
Given in the question that:-
The sum of the three consecutive multiples of 7 is = 315
Solution to the given question:-
Let us assume the three consecutive multiples of 7 be 7m, 7m+7, 7m+14
Therefore,
According to the question,
7m+(7m+7)+(7m+14) = 315
7m+7m+7+7m+14 = 315
7m+7m+7m+7+14 = 315
21m+21 = 315
21(m+1) = 315
m+1 = 315/21
m+1 = 15
m = 15-1
m = 14
Therefore, we got m = 14
Now,
The three consecutive multiples of 7 are:-
First multiple of 7 = 7m
= 7×14
= 98
The second multiple of 7 = 7m+7
= 7×14+7
= 98+7
= 105
And the third multiple of 7 = 7m+14
= 7×14+14
= 98+14
= 112
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