The sum of three consecutive multiples of 7 is 357. Find the smallest multiple. [ ]
a) 112 b) 126 c) 119 d) 116
Answers
Answered by
10
Answer:
a)112 is the smallest multiple.
Answered by
18
Let the consecutive number be x,x+1x+2
Multiple of 7=7(x),7(x+1),7(x+2)=7x,+7,7x+14
Their sum=357
Therefore,
7x+7x+7+7x+14=357
21x+21=357
21x=357-21
x=336/21
x=16
Therefore,
First multiple=7x=7*16=112
Second multiple =7x+7=7*16+7=119
Third multiple=7x+14=7*16+14=126
Therefore lowest multiple is 7x that is 112
Multiple of 7=7(x),7(x+1),7(x+2)=7x,+7,7x+14
Their sum=357
Therefore,
7x+7x+7+7x+14=357
21x+21=357
21x=357-21
x=336/21
x=16
Therefore,
First multiple=7x=7*16=112
Second multiple =7x+7=7*16+7=119
Third multiple=7x+14=7*16+14=126
Therefore lowest multiple is 7x that is 112
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