Question

the sum of three consecutive multiples of 7 is 399 find the multiples​

Answer 1

Answer:

Multiples are 133, 140, 147

Step-by-step explanation:

Given  

x

x+7

x+14

x+x+7+x+14=399

3x+21=399

3x=399-21

3x= 378

x=378/3

x=126

Multiples are 133, 140, 147

Hope it helps you my Friend

Answer 2

Answer:

Step-by-step explanation:

let the multiple be x

7(x)+7(x+1)+7(x+2)=399

7(x)+7(x)+7+7(x)+14=399

21(x)+21=399

21(x)=399-21

21(x)=378

x=378/21

x=18

therefore

multiples are 18,36,54