The sum of three consecutive multiples of 7 is 420. Find these multiples.
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Given :
- The sum of three consecutive multiples of 7 is 420.
To find :
- these multiples.
Solution :
⇒ Let's find the multiples of 7.
- 7 × 1 = 7
- 7 × 2 = 14
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⇒ Now, let's find the multiples.
→ x + (x + 7) + (x + 14) = 420
→ (x + x + x) + (7 + 14) = 420
→ (3x) + (21) = 420
→ 3x + 21 = 420
→ 3x = 420 - 21
→ 3x = 399
→ x = 399/3
→ x = 133
∴ x = 133
The consecutive multiples are :
⇒ x = 133
⇒ x + 1 = 133 + 1 = 134
⇒ x + 2 = 133 + 2 = 135
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