Question

the sum of three consecutive multiples of 7 is 63. find the largest Multiple.
Options -
A] 14
B] 21
C] 28
D] 35

Answer 1

Answer:

14 , 21 and 28

Step-by-step explanation:

Let x be a multiple of 7.

∴ The next two consecutive multiples of 7 are x + 7 + 7 + 7 (i.e. x + 14).

Thus, the three consecutive multiples of 7 are: 14, 21 and 28.

Answer 2

$\huge\boxed{\fcolorbox{black}{pink}{Solution}}$

$Let \: the \: three \: multiples \: be  \\ 7x,7x+7 and 7x+14.$

$According \: to \: the \: question,$

$7x+7x+7+7x+14 \: = \: 63$

$21x+21 \: = \: 63$

$21x \: = \: 63 \: − \: 21$

$x \: = \: \frac{42}{21}$

$x=2$

$So,$

$7x=14$

$7x+7=21$

$7x+14=28$

Therefore , the largest multiple is option (c) 28