Question

The sum of three consecutive multiples of 7 is 63. Find these multiples.

Answer 1

let the three multiples be 7x,7x+7and 7x+14
7x+7x+7+7x+14=63
21x+21=63
21x=63-21
x=42/21
x=2
so...
7x=14
7x+7=21
7x+14=28

Answer 2

Concept:

First assume the first multiple of 7 as a variable and then form a mathematical equation on solving which we get the required result.

Given:

Given that the sum of three consecutive multiples of 7 is 63.

Find:

The values of these three multiples of 7.

Solution:

Let the first multiple of 7 be = x

then the next two multiples are given by = x+7, x+7*2 = x+7, x+14

According given condition the sum of them is 63 then,

x + (x+7) + (x+14) = 63

x + x + 7 + x + 14 = 63

3x + 21 = 63

3x = 63-21

3x = 42

x = 42/3

x = 14

Then the first multiple is 14.

Next two are = 14+7, 14+14 = 21, 28

Hence the sum of the multiples of 7 that are given by 14, 21, 28 is 63.

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