Question

The sum of three consecutive
multiples of 7
is 63. Find these
multiples?​

Answer 1

Answer:

yyvg 5h8

sol:56×3257=3455666098

Answer 2

Answer:

$\red{ \boxed{\texttt{Answer}}}$

Let three consecutive multiples of 7 be 7x,7x+7 and 7x+14

Sum of three consecutive multiples of 7 = 63

7x+7x+7+7x+14 = 63

21x+21 = 63

21(x+1) = 63

(x+1) = 63/21

x+1 = 3

x = 2

therefore,

The multiples are 7(2) = 14

7x+7 = 14+7 = 21

7x+14 = 14+14 = 28