The sum of three consecutive multiples of 7 is 63. Find these multiples.let the mulpiles of 7 be x
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Let 1st Multiple be = x
so 2nd multiple = x+7
so 3rd multiple = x+7+7
=x+14
According to question -
x+(x+7)+(x+14) = 63
3x+21 = 63
3x = 63-21
x = 42/3
x = 14
So the 1st multiple = x
= 14
So 2nd multiple = x+7
= 14+7
= 21
So 3rd multiple = x+14
= 14+14
= 28
so 2nd multiple = x+7
so 3rd multiple = x+7+7
=x+14
According to question -
x+(x+7)+(x+14) = 63
3x+21 = 63
3x = 63-21
x = 42/3
x = 14
So the 1st multiple = x
= 14
So 2nd multiple = x+7
= 14+7
= 21
So 3rd multiple = x+14
= 14+14
= 28
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