Question

The sum of three consecutive multiples of 7 is 777.find these multiples

Answer 1

Answer:

let 1st number be 7x

let 2nd number be 7x+7=7(x+1)

let 3rd numbrr be 7x+14=7(x+2)

$according \: to \: question \\ 7x + 7(x + 1) + 7(x + 2) = 777 \\ 7x + 7x + 7 + 7x + 14 = 777 \\ 7( x + x + 1 + x + 2) = 7 \times 111 \\ left \: sided \: seven \: cut \: by \: right \: sided \: seven \\ 3x + 3 = 111 \\ 3(x + 1) = 111 \\ x + 1 = \frac{111}{3} \\ x + 1 = 37 \\ x = 36$

so 1st number is (7×36)=252

2nd number=7(36+1)=7×37=259

3rd number=7(36+2)=7×38=266

MARK ME BRAINLEIST

I WILL WORK HARD ON THIS QUESTION

Answer 2

Answer:

ʜᴇɴᴄᴇ,ᴛʜᴇ ʀᴇǫᴜɪʀᴇᴅ ᴍᴜʟᴛɪᴘʟᴇs ᴀʀᴇ 252,252+7=259, 259+7=266