The sum of three consecutive multiples of 7 is 777. Find these multiples.
(Hint: Three consecutive multiples of 7 are ‘x’, ‘x + 7’, ‘x + 14’)
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Answered by
249
Given the three consecutive multiples of 7 are 'x' , 'x+7' , 'x+14'
Their sum = x+x+7+x+14 = 777
⇒ 3x + 21 = 777
⇒ 3x = 777-21 = 756
⇒ x = 756/3 = 252 .
Therefore three consecutive multiples of 7 are (x) = 252
(x+7) = 252 + 7 = 259
(x+14) = 252 + 14 = 266 .
Their sum = x+x+7+x+14 = 777
⇒ 3x + 21 = 777
⇒ 3x = 777-21 = 756
⇒ x = 756/3 = 252 .
Therefore three consecutive multiples of 7 are (x) = 252
(x+7) = 252 + 7 = 259
(x+14) = 252 + 14 = 266 .
Answered by
93
x+(x+7)+(x+14)=777
3x+21 =777
3x = (777-21)
x= 756/3
=252
x+7= 252+7=259
x+14=252+14=266
3x+21 =777
3x = (777-21)
x= 756/3
=252
x+7= 252+7=259
x+14=252+14=266
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