the sum of three consecutive multiples of 7 is 777 find these multiples
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Heya friend,
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Let the first consecutive multiples of 7 be 7x.
Then,
second consecutive multiples of 7 = 7(x+1)
third consecutive multiples of 7 = 7(x+2)
According to question,
7x + 7(x+1) + 7(x+2) = 777
=> 7x + 7x + 7 + 7x + 14 = 777
=> 21x + 21 = 777
=> 21x = 777 - 21
=> 21x = 756
=> x = 756/21
=> x = 36
Hence, the first consecutive multiples of 7
= 7 × 36 = 252
Second consecutive multiples of 7 = 7 × 37 = 259
Third consecutive multiples of 7 = 7 × 38 = 266.
Thanks
With regards@
Tanisha
______________________________
Let the first consecutive multiples of 7 be 7x.
Then,
second consecutive multiples of 7 = 7(x+1)
third consecutive multiples of 7 = 7(x+2)
According to question,
7x + 7(x+1) + 7(x+2) = 777
=> 7x + 7x + 7 + 7x + 14 = 777
=> 21x + 21 = 777
=> 21x = 777 - 21
=> 21x = 756
=> x = 756/21
=> x = 36
Hence, the first consecutive multiples of 7
= 7 × 36 = 252
Second consecutive multiples of 7 = 7 × 37 = 259
Third consecutive multiples of 7 = 7 × 38 = 266.
Thanks
With regards@
Tanisha
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