Question

the sum of three consecutive multiples of 7 is, 777. find these multiples​

Answer 1

let the 3 consecutive no.s be x, x+7 and x+14

A/Q,

=> x + x + 7 + x + 14 = 777

=> 3x + 21 = 777

=> 3x = 756

=> x = 252

therefore the no.s are 252, 259, and 266

Answer 2

Answer:

Let the first multiple of 7 be x

Second multiple = (x+7)

Third multiple = (x+14)

Sum = 777

⇒ x + (x+7) + (x+14) = 777

3x + 21 = 777

3x = 777 - 21

3x = 756

x = 756/3

x = 252

x = 252

x + 7 = 259

x + 14 = 266

The multiples are:

252, 259 and 266

VERIFY:

x + (x+7) + (x+14) = 777

252 + 259 + 266 = 777

777 = 777

LHS = RHS

Hence, verified

Hope it helps

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