Question

The sum of three consecutive multiples of 7 is 777. Find these multiples​

Answer 1

Step-by-step explanation:

given,the three consecutive multiples of 7 will be of the form:

x,x+7 and x+14

Then according to the question,

x+x+7+x+14=777

3x+21=777

3x=756

x=

3

756

=252

Multiples are 252,259,266.

hope it works

Answer 2

AnswEr:

ɢɪᴠᴇɴ:

$\quad\bullet\normalsize\sf\ Sum \: of \: three \: consecutive \\ \quad\normalsize\sf\ numbers \: is \: 777$

ᴛᴏ ғɪɴᴅ:

$\quad\bullet\normalsize\sf\ Three \: Multiples$

sᴏʟᴜᴛɪᴏɴ:

$\underline{\bigstar\:\sf{According \: to \: given \: in \: question:}}$

⋆$\normalsize\sf\ Let \: the \: 1st \: multiple \: be \: 7 \left( x \right)$

⋆$\normalsize\sf\ Let \: the \: 2nd \: multiple \: be \: 7(x+1)$

⋆$\normalsize\sf\ Let \: the \: 3rd \: multiple \: be \: 7(x+2)$

Now;

$\twoheadrightarrow\normalsize\sf\ 7(x) + 7(x + 1) + 7(x + 2)= 777$

$\twoheadrightarrow\normalsize\sf\ 7x + 7x + 7 + 7x + 14 = 777$

$\twoheadrightarrow\normalsize\sf\ 21x + 21 = 777$

$\twoheadrightarrow\normalsize\sf\ 21x = 777 - 21$

$\twoheadrightarrow\normalsize\sf\ 21x = 756</p><p>$

$\twoheadrightarrow\normalsize\sf\ x = \frac{\cancel{756}}{\cancel{21}}$

$\twoheadrightarrow\normalsize\sf\ x = 36$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

⋆$\normalsize\sf\ The \: 1st \: multiple \: = \: 7 \left( x \right)$

$\dashrightarrow\sf\ 7(x) = 7 \times\ x$

$\dashrightarrow\sf\ 7(x) = 7 \times\ 3$

$\dashrightarrow\sf\ 7(x) = 252$

⋆$\normalsize\sf\ The \: 2nd \: multiple \: = \: 7 \left( x + 1 \right)$

$\dashrightarrow\sf\ 7(x+1) = 7 \times\ x + 7 \times\ 1$

$\dashrightarrow\sf\ 7(x +1) = 7 \times\ 36 + 7$

$\dashrightarrow\sf\ 7(x + 1) = 259$

⋆$\normalsize\sf\ The \: 3rd \: multiple \: = \: 7 \left( x + 2 \right)$

$\dashrightarrow\sf\ 7(x+2) = 7 \times\ x + 7 \times\ 2$

$\dashrightarrow\sf\ 7(x+2) = 7 \times\ 36 + 14$

$\dashrightarrow\sf\ 7x = 266$

$\maltese\:\underline{\textsf{Hence,\: multiples \: are}{\textbf{\: 252,259 \& 266}}}$