Question

The sum of three consecutive multiples of 7 is 777, find these multiples. (Hint:Three consecutive multiples are ×, ×+7×+14)​

Answer 1

Let the first number be x

then, second number will be x + 7

And, third number will be x + 14

ACCORDING TO QUESTION -

$(x) + (x + 7) + (x + 14) = 777 \\ = > x + x + x + 7 + 14 = 777 \\ = > 3x + 21 = 777 \\ = > 3x = 777 - 21 \\ = > 3x = 756 \\ = > x = \dfrac{756}{3} \\ = > x = 252$

Hence,

• 1st required number = 252
• 2nd required number = (252+7) = 259
• 3rd required number = (252+14) = 266

Answer 2

Numbers are 252, 259, 266

Given : Sum of Three Consecutive Multiples of 7 is 777

To Find : Three Numbers

Step By Step Explanation :

The Three consecutive multiples of 7 will be $\textsf{x, x + 7}$ and $\textsf{x + 14}$. As their Sum is 777, We can write it as follows :

$\longrightarrow\textsf{x + (x + 7) + (x + 14) = 777}$

$\longrightarrow\textsf{x + x + 7 + x + 14 = 777}$

$\longrightarrow\textsf{3x + 7 + 14 = 777}$

$\longrightarrow\textsf{3x + 21 = 777}$

$\longrightarrow\textsf{3x + 21 - 21 = 777 - 21}$

$\longrightarrow\textsf{3x = 756}$

$\longrightarrow\textsf{x = 756/3}$

$\longrightarrow\textbf{x = 252}$

• Now Three Numbers are $\textsf{x, x + 7}$ and $\textsf{x + 14}$. Substitute the value of x in each and we get 252, 259, 266.

Therefore, Numbers are 252, 259, 266