Math, asked by Jassu2008, 1 month ago

The sum of three consecutive multiples of 7 is 777 Find these multiples

(Hint: Three consecutive multiples of 7 are x;x+7;x+14)​

Answers

Answered by Mansidhakar10
2

Answer:

x+x+7+x+14=777

3x+21=777

3x=777-21

3x=756

x=756/3

x=252

x=252

x+7=259

x+14=266

HOPE IT WILL HELP U

Answered by varadad25
5

Answer:

The three consecutive multiples of 7 are 252, 259, 266.

Step-by-step-explanation:

Let the first multiple of 7 be 7x.

∴ The consecutive further two multiples are ( 7x + 7 ) and ( 7x + 14 ).

From the given condition,

The sum of three consecutive multiples of 7 is 777.

7x + ( 7x + 7 ) + ( 7x + 14 ) = 777

⇒ 7x + 7x + 7 + 7x + 14 = 777

⇒ 7x + 7x + 7x + 7 + 14 = 777

⇒ 7 ( x + x + x + 1 + 2 ) = 777

⇒ 3x + 3 = 777 ÷ 7

⇒ 3x + 9 = 111

⇒ 3 ( x + 1 ) = 111

⇒ x + 1 = 111 ÷ 3

⇒ x + 1 = 37

⇒ x = 37 - 1

x = 36

Now,

The first multiple = 7x = 7 * 36 = 252

Second multiple = 7x + 7 = 252 + 7 = 259

Third multiple = 7x + 14 = 252 + 14 = 266

The three consecutive multiples of 7 are 252, 259, 266.

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