Question

the sum of three consecutive multiples of 7 is 777.find these multiples​

Answer 1

Answer:

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Answer 2

★ Solution :-

We know that three multiples that add up to 777 are consecutive that means they are the continuous three multiples of 7.

We also know that each multiple of 7 will be 7 greater than the first multiple and third multiple will be 14 greater than the first multiple.

Let the consecutive multiples of 7 be y, y+7 and y+14 respectively.

According to the question,

$\sf \leadsto y + (y + 7) + (y + 14) = 777$

$\sf \leadsto y + y + y + 7 + 14 = 777$

$\sf \leadsto 3y + 21 = 777$

$\sf \leadsto 3y = 777 - 21$

$\sf \leadsto 3y = 756$

$\sf \leadsto y = \dfrac{756}{3}$

$\sf \leadsto y = 252$

Now, we can find the second and third consecutive multiple.

Second multiple :

$\sf \leadsto y + 7$

$\sf \leadsto 252 + 7$

$\sf \leadsto 259$

Third multiple :

$\sf \leadsto y + 14$

$\sf \leadsto 252 + 14$

$\sf \leadsto 266$

Therefore, the consecutive multiples of 7 that add upto 777 are 252, 259 and 266 respectively.