Question

the sum of three consecutive multiples of 7 is 777. find these numbers

Answer 1

$\mathbf{solution}$

Let numbers are 7x, 7( x + 1 ) and 7( x + 2 )



Given, their sum = 777


7x + 7( x + 1 ) + 7( x + 2 ) = 777


x + x + 1 + x + 2 = 111


3( x + 1 ) = 111


x + 1 = 37


x = 36






Number are

7x = 7(36) = 252
7( x + 1 ) = 7(37) = 259
7( x + 2 ) = 7(38) = 266

Answer 2

let the multiples of 7 are

7x+14x+21x = 777

42x = 777

x = 777/42 = 18.5

x = 18.5

7x = 7 * 18.5 = 129.5

14x = 14 * 18.5 = 259

21x = 21 * 18.5 = 388.5

so the three numbers are 129.5 and 259 and 388.5

verification -

129.5+259+388.5 = 777.

hope it helps you.