The sum of three consecutive multiples of 7 is 777.Find theese multiples.
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um of 3 consecutive multiples of 7 is 777.
Let the consecutive multiples of 7 be 7n, (7n + 7) and (7n + 14).
⇒ (7n) + (7n + 7) + (7n + 14) = 777
⇒ 21n + 21 = 777
⇒ 21n = 756
⇒ n = 36
Therefore, multiples of 7 whose sum is 777 are (7 x 36), (7 x 36) + 7 and (7 x 36) + 14.That is 252, 259 and 266.
kaira1818:
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Let the three consecutive multiple of 7 be 7x
(7x + 7) (7x + 14)
(7x) + (7x + 7) + (7x + 14) = 777
21x + 21 = 777
21x = 777 - 21
21x = 756
x = 756/21
x = 36
Multiple of 7 whose sum is 777 are (7×36) , (7×36) + 7 , (7×36) + 14
That is 252, 259 and 266.
Hence Solved
Hope it's helpful
(7x + 7) (7x + 14)
(7x) + (7x + 7) + (7x + 14) = 777
21x + 21 = 777
21x = 777 - 21
21x = 756
x = 756/21
x = 36
Multiple of 7 whose sum is 777 are (7×36) , (7×36) + 7 , (7×36) + 14
That is 252, 259 and 266.
Hence Solved
Hope it's helpful
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