Question

the sum of three consecutive multiples of 7 is 777. find the multiples​

Answer 1

Let 7x, 7(x + 1) and 7(x + 2) be the three consecutive numbers.

7x + 7(x + 1) + 7(x + 2) = 777

21x + 21 = 777

21x = 756

x = 36

Hence, the numbers are 252, 259, 266.

Answer 2

Answer:

252, 259, 266

Step-by-step explanation:

Let the three consecutive multiples be x

therefore it will be, x, x + 7 and x + 14  

now the equation:

x + ( x + 7) + ( x + 14) = 777

then open the brackets

x + x + 7 + x + 14 = 777

Take the variables and numbers on 2 different sides

x + x + x = 777 - 7 - 14

then calculate it:

3x = 756

therefore x =  $\frac{756}{3}$

Which is equal to = 252

now take the equation and substitute it

x + ( x + 7) + ( x + 14) ⇒ 252 + ( 252 + 7) + ( 252 + 14)

which is:  252, 259, 266

Hope you got it :)