the sum of three consecutive multiples of 7 is zero.
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Answer:
x+(x+7)+(x+14)=0
x+x+7+x+14=0
3x+21=0
3x=0-21
3x=-21
x=-21/3
x=-7
so the integers are.
-7,-14,-21
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Answered by
5
Answer:
Let the numbers be 7a , 7a + 7 and 7a +14
Let the numbers be 7a , 7a + 7 and 7a +14According to question,
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0=> 21a = -21
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0=> 21a = -21=> a = -1
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0=> 21a = -21=> a = -1First number = 7(-1) = -7
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0=> 21a = -21=> a = -1First number = 7(-1) = -7Second number = 7(-1) + 7
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0=> 21a = -21=> a = -1First number = 7(-1) = -7Second number = 7(-1) + 7= -7 + 7
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0=> 21a = -21=> a = -1First number = 7(-1) = -7Second number = 7(-1) + 7= -7 + 7= 0
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0=> 21a = -21=> a = -1First number = 7(-1) = -7Second number = 7(-1) + 7= -7 + 7= 0Third number = 7(-1) +14
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0=> 21a = -21=> a = -1First number = 7(-1) = -7Second number = 7(-1) + 7= -7 + 7= 0Third number = 7(-1) +14= -7 + 14
Let the numbers be 7a , 7a + 7 and 7a +14According to question,7a + 7a +7 +7a + 14 = 0=> 21a + 21 = 0=> 21a = -21=> a = -1First number = 7(-1) = -7Second number = 7(-1) + 7= -7 + 7= 0Third number = 7(-1) +14= -7 + 14= 7
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