The sum of three consecutive multiples of 7 is777. Fine these multiples?
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sum of 3 consecutive multiples of 7is777.
let the consecutive multiples of 7 be 7n, (7n+7)and (7n+14)
=(7n) +(7n+7)+(7n+14)=777
=21n+21=777
=21n=756
=n=36
therefore multiples of 7 whose sum is 777 are (7 x 36),(7 x 36)+7 and (7 x 36)+14.that is 252,259 and 266
let the consecutive multiples of 7 be 7n, (7n+7)and (7n+14)
=(7n) +(7n+7)+(7n+14)=777
=21n+21=777
=21n=756
=n=36
therefore multiples of 7 whose sum is 777 are (7 x 36),(7 x 36)+7 and (7 x 36)+14.that is 252,259 and 266
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