Question

the sum of three consecutive multiples of 7is 777.find these multiples

Answer 1

Let the three multiples of seven be k, k+7, k+14


These numbers have a common difference of seven. It is because we are taking multiples of 7. So we need to add 7 to each successive term.



Sum of the three consecutive multiples is 777.

So, we have:

$k+(k+7)+(k+14)=777 \\ \\ \implies 3k+21=777 \\ \\ \implies 3k = 756 \\ \\ \implies k = \frac{756}{3} \\ \\ \implies k = 252$

Thus, the three multiples of seven are:

k = 252
k+7 = 252+7 = 259
k+14 = 252+14 = 266


So, the numbers are 252, 259, 266

Answer 2

Given : The sum of 3 consecutive multiples of 7 is 777 .

To Find : Those 3 consecutive multiples.

Solution :

Let us consider the shortest Multiple as 7x .

The 2 Nd Multiple = 7x+7

The 3 rd multiple = 7x+14 .

Now ,

According to the Question :

7x+7x+7+7x+14 = 777

21x+21 = 777

(x+1)21= 777

(x+1) = 777/21 = 37

x+1 = 37

x= 37-1 = 36

Now ,

The numbers are :

7x = 252

7x+7 = 259

7x+14 = 266

#Be Brainly !!