Question

The sum of three consecutive multiples of 7is777.find these multiple

Answer 1

Given :

The sum of three consecutive multiples of 7is777.find these multiple

To find :

Find multiples of number

Solution :

Let the number be x

According to question

=> 7x + 7(x+1) + 7(x+2) = 777

=> 7x + 7x + 7 + 7x + 14 = 777

=> 21x + 21 = 777

=> 21x = 777 - 21

=> 21x = 756

=> x = 756/21

=> x = 36

First multiple = 7x = 7× 36 = 252

Second multiple = 7(x+1) = 7(36+1) = 259

Third multiple = 7(x+2) = 7(36+2) = 266

Answer 2

$\bf\green{\underline{\underline{\bf{\red{Question}}}}}$

The sum of three consecutive multiples of 7is777. Fnd these multiple

$\bf\green{\underline{\underline{\bf{\red{To\:find}}}}}$

Find these multiple

$\bf\green{\underline{\underline{\bf{\red{Solution}}}}}$

Let the first multiple be 7z , second multiple be 7(z+1) and third multiple be 7(z+2)

According to the given condition

Sum of three consecutive multiple = 777

$\hookrightarrow\sf 7z+7(z+1)+7(z+2)=777$

$\hookrightarrow\sf 7z+7z+7+7z+14=777$

$\hookrightarrow\sf 21z+21 = 777$

Taking 21 as a common

$\hookrightarrow\sf 21(z+1)=777$

$\hookrightarrow\sf z+1=\Large\frac{777}{21}$

$\hookrightarrow\sf z+1=37$

$\hookrightarrow\sf z=37-1=36$

$\large{\boxed{\bf{z=36}}}$

$\therefore$ First multiple =7z=7×36=252

Second multiple = 7(z+1) = 7(36+1) = 259

Third multiple = 7(z+2) = 7(36+2) = 266

$\bf\green{\underline{\underline{\bf{\red{Verification}}}}}$

Sum of three consecutive multiple

= (252+259+266)

= 777

Hence, it is verified