Question

the sum of three consecutive multiples of 8 is 264 find the numbers

Answer 1

Let the multiples be 8a, 8a + 8 and 8a + 16

According to question,

8a + 8a + 8 + 8a + 16 = 264

=> 24a + 24 = 264

=> 24a = 240

=> a = 10

First multiple = 8 × 10 = 80

Second multiple = 80 + 8 = 88

Third multiple = 80 + 16 = 96

Answer 2

Let three consecutive multiples of 8 are x , x + 8 and x + 16.



According to question,

x + x + 8 + x + 16 = 264


3x + 24 = 264


3x = 264 - 24


3x = 240


x = 80


First number = x = 80


Second number = x + 8 = 80 + 8 = 88


and

Third number = x + 16 = 80 + 16 = 96.