Question

the sum of three consecutive multiples of 8 is 888​

Answer 1

Answer:

let the concesscutive numbers be (X+8) (X+16) (X+24)

sum of the concesscutive numbers is equal to 888

(X+8)+(X+16+(X+24) = 888

X+8+X+26+X+24=888

3X+48=888

3X=888-48

3X=840

X=840/3

X=280

therefore the concesscutive numbers are (X+8) = 280+8=288

(X+16)=280+16=296

(X+24)=280+24=304

therefore the numneed are 288,296and 304.

Answer 2

➢Given :

• Sum of the three consecutive multiples of 8 = 888.

➢To find :

• We have to find the multiples of 8.

➢Solution :

• Let the three consecutive integers be x , x + 1, x + 2.

➢According to the question :

$2x + 3(x + 1) + 4(x + 2) = 74 \\ 2x + 3x + 3 + 4x + 8 = 74 \\ 9x + 11 = 74 \\ 9x = 74 - 11 \\ 9x = 63 \\ x = \frac{63}{9} = 7$

•So, x = 7, x + 1 = 7 + 1 = 8, x + 2 = 7 + 2 = 9.

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