Question

the sum of three consecutive multiples of 8 is 888 . find these number
​

Answer 1

Answer:

288, 296 and 304

Step-by-step explanation:

Let the required multiples be 8( a - 1 ) , 8a and 8( a + 1 ).

 According to qeustion :

Their sum = 888

 ⇒ 8( a - 1 ) + 8a + 8( a + 1 ) = 888

 ⇒ 8a - 8 + 8a + 8a + 8 = 888

 ⇒ 8a + 8a + 8a - 8 + 8 = 888

 ⇒ 24a = 888

 ⇒ a = 888/24

 ⇒ a = 37

Hence the required numbers are :

  8( a - 1 ) = 8( 37 - 1 ) = 8( 36 ) = 288

  8a = 296

  8a + 1 = 304

Answer 2

Step-by-step explanation:

Let the first number be 8x

Let the second number be 8(x+1)

Let the third number be 8(x+2)

Acc. to question,

8x + 8(x+1) + 8(x+2) = 888