The sum of three consecutive
multiples of
8 is 888 . Find multiples
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Answer: the third consecutive multiple of 8 will be 8 (x+2).
given = sum of three consecutive multiples of 8 is 888
thus,
8x + 8 (x+1) + 8 (x+2) = 888
8x + 8x + 8 + 8x + 16 = 888
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