Math, asked by muskansinghania36, 2 months ago

the sum of three consecutive multiples of 8 is 888 find it's multiples​

Answers

Answered by Anonymous
2

Answer:

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Step-by-step explanation:

Let the first multiple of 8 be 8x,

second consecutive multiples of 8 be 8(x + 1) and

third consecutive multiples of 8 be 8(x + 2)

it is given that some of these multiples is 888

8 x + 8 (x + 1) + 8 (x + 2) = 888

8 x + 8 x + 8 + 8 x + 16 = 888

24 x + 24 = 888

24 x = 888 - 24

24 x = 864

x = 864/24

x = 36

first multiple of 8 = 8x = 8×36 = 288

second multiple of 8 = 8(x + 1) = 8 × (36 + 1) = 296

third multiple of 8 = 8(x + 2) = 8 × (36 + 2) = 304

Answered by FιҽɾყPԋσҽɳιx
12

 \bf Question:-

The sum of three consecutive multiples of 8 is 888 find it's multiples?

Answer:

First multiple = 288

Second multiple = 296

Third multiple = 304

Step-by-step explanation:

we have to find three consecutive multiple of 8 whose sum is 888. For this we have to take multiples of 8 be x

 \sf Let \:  the \:  first \:  multiple = x

 \sf Second  \: multiple = x+8

 \sf Third  \: multiple = x+16

 \bf According \:  to \:  the \:  question :-

 \sf{x+x+18+x+16=88}

 \sf \longrightarrow3x+24=888

We write 3x because in equation there are three "x" so, we write "3x". we write 24 because we have to add 18 and 36.

\sf \longrightarrow3x=888-24

We subtract 24 with 888 because we shift L.H.S side to R.H.S and we put sign of subtract because in L.H.S there is a sign of +.

Remember:-

when we shift any number left hand side to write inside. The sign before the number is always change. For example :- 3x+24=888. We shift (+24) to R.H.S and we have to change sign of + into -.

when we shift any number left hand side to write inside. The sign before the number is always change :-

  • + = -
  • - = +
  • × = ÷
  • ÷ = ×

Back to the question:-

\sf \longrightarrow3x=864

\sf \longrightarrow \:   \dfrac{864}{3}

We cancel 864/3 on 3. We have to check 864 is cancel on 3. For this we have to add 8+6+4 = 18. we get 18, and 18 is come in table of 3. {3×6=18}.

\sf \longrightarrow \:    \cancel{\dfrac{864}{3} } = 288

\sf \longrightarrow x= 288

So, value of x is 288

Now,

So, First multiple = 288

Second multiple = x+8

= 288+8 = 296

Third multiple = x+16

= 288+16 = 304

Required Answer :-

First multiple = 288

Second multiple = 296

Third multiple = 304

Additional informatioN:-

Monomial: An algebric expression which contains only one term is called a monomial.

For example : Expression 5x, 7x²y and -2y are monomials.

Binomial: An algebraic expression which contains two terms is called a binomial.

For example : Expression 2x+3y, 7x²-4y, -2y +3xyz are binomial.

Trinomial: An algebric expression which contains three terms is called a trinomial.

For example : Expressions 2x+3y +4z, 7x²-4y²+3z, x+x²+x³ are trinomial.

Polynomial: An algebraic expression containing one or more terms is called a polynomial.

Note : A monomial, binomial and trinomial are polynomials

Expression formed by combining variables and constants using operations addition, subtraction ,multiplication and division

Variable: A letter or symbol used in expression that can take any value is called variable.

Constant: Fixed values in the expressions are called constant.

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