Question

the sum of three consecutive multiples of 8 is 888. find its multiples​

Answer 1

Answer:

Here is your Answer : )

Step-by-step explanation:

x+8 + x+16 + x+24 = 888

3x + 48 = 888

3x = 888-48

3x = 840

x = 840/3

x = 280

x+8 = 280+8 -> 288

x+16 = 280+16 -> 296

x+24 = 280+24 -> 304

Hope it helps : )

Answer 2

Let the multiples be:

• First multiple = 8x
• Second multiple = 8(x + 1) = (8x + 8)
• Third multiple = 8(x + 2) = (8x + 16)

Now, in the question, it is given that the sum of the three consecutive multiples of 8 is 888. So,

→ 8x + (8x + 8) + (8x + 16) = 888

→ 24x + 24 = 888

→ 24x = 888 – 24

→ 24x = 864

→ x = 864/24

→ x = 36

Hence,

• First multiple = 8x = (8 × 36) = 288
• Second multiple = (8x + 8) = (288 + 8) = 296
• Third multiple = (8x + 16) = (288 + 16) = 304

•°• The multiples are 288, 296 & 304 respectively.