Question

the sum of three consecutive multiples of 8 is 888.find the multiples

Answer 1

Answer:-

Given,

Sum of three consecutive multiples of 8 is 888.

Let the consecutive numbers be x , x+8 and x+16.

$\mathsf{x + x + 8 + x + 16= 888}$

$\mathsf{3x + 24= 888}$

$\mathsf{3x = 888 - 24}$

$\mathsf{3x = 864}$

$\mathsf{x = \frac{864}{3} }$

$\mathsf{x = 288}$

Value of x = 288

Therefore , the three consecutive numbers are :-

First multiple = x = 288

Second multiple = x+8 = 288+8 = 296

Third multiple = x+16= 288+16= 304

Answer 2

Answer:

288, 296, 304

Step-by-step explanation:

Let the consecutive no.s be x, x+8, x+16

ATQ,

x+x+8+x+16=888

3x+24=888

3x=888-24

3x=864

x=864÷3

x=288

First no.=288

Second no. =288+8=296

Third no.= 288+16=304