Question

the sum of three consecutive multiples of 8 is 888.find the numbers
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Answer 1

Step-by-step explanation:

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Answer 2

Solution:

Let the three consecutive multiples of 8 be 8x, 8(x+1) and 8(x+2).

Because There sum is 888

therefore, 8x + 8(x+1) + 8(x+2) = 888

8{x + (x + 1) + (x + 2)} = 888

8(3x + 3) = 888

3x + 3 = 888÷8 (dividing both side by 8)

3x + 3 = 111

3(x + 1) = 111

x + 1 = 111÷3 (dividing both side by 3)

x + 1 = 37

x = 37 -1 (transposing 1 to RHS)

x = 36

8x = 8 × 36 = 288

8(x + 1) = 8(36 + 1)

= 8 × 37 = 296

and 8(x + 2) = 8(36 + 2) = 8×38 = 304

Hence, the desired multiples are 288,296 and 304.

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