Question

the sum of three consecutive multiples of 8 is 888 , find the multiples

Answer 1

THE CONSECUTIVE MULTIPLES OF 8

FIRST  MULTIPLE = x

SECOND MULTIPLE = x+8

THIRD MULTIPLE = (x+8) + 8

                          = x+16

GIVEN,

SUM OF MULTIPLES = 888

∴ FIRST MULTIPLE + SECOND MULTIPLE + THIRD MULTIPLE

∴ x + (x+8) + (x+16) = 888

∴ x + x + x + 8 + 16 = 888

∴ 3x + 8 + 16 = 888

∴ 3x + 24 = 888

∴ 3x = 888 - 24

Answer 2

Answer:

$\huge \mathbb \purple{ANSWER\implies}$

Let the three consecutive multiples of 8 be 8x, 8x + 8 and 8x + 16.

As per the conditions, we get

8x + (8x + 8) + (8x + 16) = 888

⇒ 8x + 8x + 8 + 8x + 16 = 888

⇒ 24x + 24 = 888

⇒ 24x = 888 – 24 (transposing 24 to RHS)

⇒ 24x = 864

⇒ x = 864 ÷ 24 (transposing 24 to RHS)

⇒ x = 36

Thus, the required multiples are

36 × 8 = 288, 36 × 8 + 8 = 296 and 36 × 8 + 16 = 304,

i.e., 288, 296 and 304.