Question

the sum of three consecutive multiples of 8 is 888. Find the multiples

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Answer 1

Given:-

•Sum of 3 consecutive multiples of 8 is 888.

To find:-

•The multiples

Solution:-

Let the first multiple be 8x

Thus,the other multiples are:-

•8x+8

•8x+16

Now,As Per Question:-

=>8x+8x+8+8x+16=888

=>24x+24=888

=>24x=888-24

=>24x=864

=>x=864/24

=>x=36

Thus,the multiples are:-

•8×36=288

•8×36+8=296

•8×36+16=304

Answer 2

Given :

• Sum of three consecutive multiples of 8 is 888.

To find :

• The multiples.

According to the question,

Let the three consecutive multiples of 8 be 8x,8 (x + 1),8 (x + 2)

→ 8x + 8 (x + 1) + 8 (x + 2) = 888

→ 8x + 8x + 8 + 8x + 16 = 888

→ 24x + 24 = 888

→ 24x = 888 - 24

→ 24x = 864

→ x = 864 ÷ 24

.°. x = 36

_________________....

Value of 8x

→ 8 × 36

→ 288

_________________....

Value of 8(x + 1)

→ 8(36 + 1)

→ 8 × 37

→ 296

_________________....

Value of 8(x + 2)

→ 8(36 + 2)

→ 8 × 38

→ 304

__________________....

.°. The three consecutive multiples of 8 is 288,296 and 304...