Question

the sum of three consecutive multiples of 8 is 888. find the multiplies ​

Answer 1

Answer:

Step-by-step explanation:

a+(a+8)+(a+16)=888

3a+24=888

3a=864

a=864/3

a=288

288,296,304

46th,47th,48th multiple of 8 has the sum of three consecutive multiples of 8 =888

Answer 2

Given :-

• The sum of three consecutive multiples of 8 is 888.

To Find :-

• What are the multiples?

Solution :-

Let the 1st multiple of 8 be 8x.

Then, the 2nd and 3rd multiple of 8 will be 8( x +1) and 8 ( x +2) respectively.

As per question :-

Given that,

The sum of three consecutive multiples of 8 is 888.

Therefore,

8x + 8 ( x +1) + 8 ( x +2) = 888

⟼ 8x + 8x + 8 + 8x + 16 = 888

⟼ 24 x = 864

$⟼x = 36$

Hence,

1st multiple of 8 is = 36 × 8 = 288

2nd multiple of 8 is = 8 ( x +1) = 8 ( 36+1) = 296

3rd multiple of 8 is = 8 ( x+2) = 8 ( 36+2) = 304