the sum of three consecutive multiples of 8 is 888.find the multiples
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Answered by
1
Answer:
let three consecutive multiple be 8x, 8(x+1),8(x+2)
Step-by-step explanation:
8x+8(x+1)+8(x+2)=888
8(3x+3)=888
3x+3=888/8 =111
3x+3=111
3x=111-3
3x=108
x=108/3=36
8x=8multiply by 36
=288
8(x+1)=8(36+1)=296
8(x+2)=8(36+2)=304
so the consecutive multiple are 288,296,304
Answered by
1
Answer:
hey mate :)
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