the sum of three consecutive multiples of 8 is 888.find the multiples
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Answer:
The third consecutive multiple of 8 be 8(x+2). It is given that the sum of all the three consecutive multiples of 8 is 888. Therefore the first multiple of 8 is 8x, by substituting the value of x in the equation we get, ⇒8×36=288.
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Answered by
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Answer:
Let the three consecutive multiples of 8 be x,x+8 and x+16
Now,
x+x+8+x+16=888
3x+24=888
3x=864
x=288
Therefore, the three consecutive multiples of 8 are 288,296,304.
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