The sum of three consecutive multiples of 8 is 888. Find the multiples of 8
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The third consecutive multiple of 8 be 8(x+2). It is given that the sum of all the three consecutive multiples of 8 is 888. Therefore the first multiple of 8 is 8x, by substituting the value of x in the equation we get, ⇒8×36=288
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The third consecutive multiple of 8 be 8(x+2). It is given that the sum of all the three consecutive multiples of 8 is 888. Therefore the first multiple of 8 is 8x, by substituting the value of x in the equation we get,
⇒8×36=288
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