Question

The sum of three consecutive multiples of 8 is 888.Find the multiples

Answer 1

➡HERE IS YOUR ANSWER⬇

Let, the numbers are 8n, 8(n+1) and 8(n+2).

Given that :

8n + 8(n+1) + 8(n+2) = 888

or, 8(n + n + 1 + n + 2) = 888

or, 3n + 3 = 111

or, 3n = 108

or, n = 36

So, n = 36.

Therefore, the three consecutive multiples of 8 are

288, 296 and 304.

⬆HOPE THIS HELPS YOU⬅

Answer 2

Let the three consecutive multiples of 8 be 8x, 8(x+1) and 8(x+2).

According to the question,

8x + 8(x+1) + 8(x+2) = 888

⇒ 8 (x + x+1 + x+2) = 888 (Taking 8 as common)

⇒ 8 (3x + 3) = 888

⇒ 3x + 3 = 888/8

⇒ 3x + 3 = 111

⇒ 3x = 111 – 3

⇒ 3x = 108

⇒ x = 108/3

⇒ x = 36

Thus, the three consecutive multiples of 8 are:

8x = 8 × 36 = 288

8(x + 1) = 8 × (36 + 1) = 8 × 37 = 296

8(x + 2) = 8 × (36 + 2) = 8 × 38 = 304