Question

the sum of three consecutive multiples of 8 is 888.find the multiples?​

Answer 1

Answer:

The third consecutive multiple of 8 be 8(x+2). It is given that the sum of all the three consecutive multiples of 8 is 888. Therefore the first multiple of 8 is 8x, by substituting the value of x in the equation we get, ⇒8×36=288.

Answer 2

Let the three consecutive multiples of 8 be 8x, 8(x+1) and 8(x+2).

According to the question,

8x + 8(x+1) + 8(x+2) = 888

⇒ 8 (x + x+1 + x+2) = 888 (Taking 8 as common)

⇒ 8 (3x + 3) = 888

⇒ 3x + 3 = 888/8

⇒ 3x + 3 = 111

⇒ 3x = 111 – 3

⇒ 3x = 108

⇒ x = 108/3

⇒ x = 36

Thus, the three consecutive multiples of 8 are:

8x = 8 × 36 = 288

8(x + 1) = 8 × (36 + 1) = 8 × 37 = 296

8(x + 2) = 8 × (36 + 2) = 8 × 38 = 304