Question

the sum of three consecutive multiples of 8 is 888.find the multiples

Answer 1

hey friend...... :-)

Here is your answer

suppose three multiples are x-1,x,x+1 th multiples of 8.

Their sum is 888. So, 8(x-1)+8x+8(x+1)=888

24x=888

3x=111.

x=111/3=37.
Multiples are:

8(x-1)=8*36=288
8*37=296

8*38=304.

Hoping it helps

Thanks :D

Answer 2

$\huge\boxed{\red{\bold{Solution}}}$

✍ let the three consecutive number be x, (x +8) , (x + 16 )..✌

⭐ x + (x +8)+(x+16) = 888

=> x + x+8 + x + 16 = 888

=> 3x + 8 + 16 = 888

=> 3x + 24 = 888

=>3x = 888- 24

=> 3x = 864

=> x = 864/ 3

=> x = 288

So , x = 288

⭐ (x + 8) = 288 + 8 = 296

⭐( x + 16) = 288 + 16 = 304

Hence ,

Three consecutive number be 288, 296 and 304..