Question

The sum of three consecutive multiples of 8 is 888.Find the multiples.​

Answer 1

Answer:

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Answer 2

☯Let the three Consecutive multiples of 8 be 8x,8(x + 1) and 8(x + 2).

${\underline{\boldsymbol{\pink{According~ to~ the~ question~ :}}}}$

8x + 8(x + 1) + 8(x + 2) = 888

$\sf{8(x + x + 1 + x + 2) = 888 \{taking \: 8 \: as \: common \}}$

$:\implies\sf{8(3x+3)=888}$

$:\implies\sf{3x+3=888/8}$

$:\implies\sf{3x=111-3}$

$:\implies\sf{3x=108}$

$:\implies\sf{x=108/3}$

$:\implies{\boxed{\frak{\purple{x=36}}}}$

Thus,the three consecutive multiples of 8 are :

• ${\underline{\frak{\purple{8x=8 × 36=288}}}}$

• ${\underline{\frak{\purple{8(x+1)=8 × (36+1)=8×37=296}}}}$

• ${\underline{\frak{\purple{8(x+2)=8×(36+2)=8×38=304}}}}$

$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {\underline{\textsf{\textbf{Hence,Solved!!!!}}}}$