The sum of three consecutive multiples of 8 is 888.Find the multiples.
Answers
Answer:
the multiples are 288,296,304
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Given:
✰ The sum of three consecutive multiples of 8 is 888.
To find:
✠ The multiples.
Solution:
First we will assume the three consecutive multiples as x + 8 , x + 16 and x + 24 respectively. In this question, it is given that the sum of three consecutive multiples of 8 is 888 and we have to find the three consecutive multiples. As we know that multiples of 8 are 16 , 24 , 32 and so on basically the table of 8. Thus, forming an adequate equation and doing required calculations, we will find the respective multiplies.
Let the three consecutive multiples be + 8 , x + 16 and x + 24 respectively.
According to the Question :
⟼ (x + 8) + (x + 16) + (x + 24) = 888
⟼ x + 8 + x + 16 + x + 24 = 888
⟼ x + x + x + 8 + 16 + 24 = 888
⟼ 3x + 8 + 16 + 24 = 888
⟼ 3x + 48 = 888
⟼ 3x = 888 - 48
⟼ 3x = 840
⟼ x = 840/3
⟼ x = 280
Now, we will substitute the value of x in respective multiplies we have assumed, we have:
➣ First Multiple = x + 8
➣ First Multiple = 280 + 8
➣ First Multiple = 288
➣ Second Multiple = x + 16
➣ Second Multiple = 280 + 16
➣ Second Multiple = 296
➣ Third Multiple = x + 24
➣ Third Multiple = 280 + 24
➣ Third Multiple = 304
∴ The three respective multiplies are 288, 296 and 304 respectively.
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