Question

The sum of three consecutive multiples of 8 is 888 . Find the multiple.​

Answer 1

Answer:

Let the first multiple of 8 be 8x. Also the third consecutive multiple of 8 will be8(x+2). => x = 36. If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

Step-by-step explanation:

hope it help uh freind

Answer 2

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Let 3 consecutive multiple of 8

8x,8(x+1),8(x+2)

Sum=8x+8(x+1)+8(x+2)=888

8(x+x+x+1+2)=888

3(x+1)=111

x+1= 111/3

x+1=37

x=36

First multiple =8x=8×36=288

Second =8(x+1)=8×37=296

Third =8(x+2)=8×38=304