Question

The sum of three consecutive multiples of 8 is 888. Find the multiples.​

Answer 1

Answer:

Let the first multiple of 8 be 8x.Therefore the second consecutive multiple of 8 will be 8(x+1)Also the third consecutive multiple of 8 will be 8(x+2).It is given that the sum of these three consecutive multiples of 8 is 888=> 8x + 8(x+1) + 8(x+2) = 888=> 8x + 8x + 8 + 8x + 16 = 888=> 24x + 24 = 888Take 24 on the RHS=> 24x = 888 - 24=> x = 864/24=> x = 36.Therefore First multiple of 8 be 8x = 8 x 36 = 288Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

Step-by-step explanation:

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Answer 2

Answer :-

The 3 consecutive multiples of 8 which sum up to 888 are: 288, 296 and 304.

Step-by-step explanation :-

We know that the 3 consecutive multiples are

x, (x + 1), (x + 2).

Since the 3 consecutive multiples of 8 is given in the question, these 3 multiples can be considered as:

• 8x
• 8 (x + 1)
• 8 (x + 2)

★ According to the question,

The sum of these 3 multiples is 888.

8x + 8 (x + 1) + 8 (x + 2) = 888

⇒ 8x + 8x + 8 + 8x + 16 = 888

⇒ 24x + 24 = 888

⇒ 24x = 888 - 24

⇒ 24x = 864

⇒ x = 864 ÷ 24

⇒ x = 36

Finding the multiples:

• 8x = 8(36) = 288
• 8 (x + 1) = 8 (37) = 296
• 8 (x + 2) = 8 (38) = 304

VERIFICATION:

When we take the sum of these multiples, the answer comes to be 888 which was asked in the question.

288 + 396 + 304

= 888

= RHS

✰ LHS = RHS

Hence verified